What is the angle between (AXB) and
(А+b)
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two vectors A and B.
A and B are two vectors.So,their sum A+B
lies in the same plane where A and B lie (since they are non-parallel so they define a plane and cross product between them is not zero.)
A×B=|A| |B| sin×alpha×n,where alpha is the angle between A and B and n is the unit vector perpendicular to the plane containing A and B
So,the angle between (A+B) and (A×B) is 90°.
Mathematically,=|A+B||A×B|cos alpha=(A+B).(A×B)
=A.(A×B)+B.(A×B)
=B.(A×A)+A.(B+B)
=0+0
Answer is 90°(degree)✔
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