Question

what is the angle between two equal forces so that their resultant is 1/3 of either for​

Answer 1

Answer:

your answer is

Explanation:

Lets the vectors be the x and x

and resultant will be 31x

Req=R12+R22+2R1R2Cosθ

According to given condition: 

(31x)2 =x2+x2+2x2cosθ

9x2 = 2x2+2x2cosθ

cosθ=181−1

θ=cos−1(18−17)

Here A=F; B=F; R=F; θ=?

Now R=A2+B2+2ABcosθ

F=F2+F2+2F.F.cosθ

=F2(1+cosθ)

⇒1=2(1+cosθ)

cosθ=−21=cos120o

⇒θ=120o

hope it helps you

Answer 2

Answer:

120 degree

Explanation:

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