What is the angle between vectors 2i + 4j + 5k and 3i + 2j + k.
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dot product: 6 + 8 + 5 = 19
magnitudes are : √(4+16+25) = 3√5
and √(9+4+1) = √14
cosine of angle Ф = 19 /[3√5 * √14]
angle = 40.8 deg.
magnitudes are : √(4+16+25) = 3√5
and √(9+4+1) = √14
cosine of angle Ф = 19 /[3√5 * √14]
angle = 40.8 deg.
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