Question

what is the angle for which the maximum height reached and corresponding range are equal.explain​

Answer 1

Answer:

In projectile thrown at angle θ Range R and maximum height H are given as :

Range, R=gu2(sin2θ)=gu22sinθcosθ

Maximum Height, H=2gu2sin2θ

Given: H=R

gu2(2sinθcosθ)=2gu2sin2θ

4cosθ=sinθ

tanθ=4

θ=760

Explanation:

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