Question

what is the angle of inclination if the weight of 150 kg is in equilibrium and the value of m is 0.5773

Answer 1

Explanation:

m = tan theta = 0.5773

=> theta = tan inverse (0.5773)

Hope this is very helpful for you

Answer 2

The given question is the weight of 150 kg is in equilibrium and the value of m is 0.5773.

Here, we have to find the angle of inclination.

The slope of the object m= tan theta

the angle of inclination is theta.

The tan theta is given as 0.5773

then theta =

${tan}^{ - 1} m$

${tan}^{ - 1} 0.5773$

theta= 0.52 approximately in degree

theta=29.99 in radian

The above answer is the final

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