What is the angle of projection at which horizontal range and maximum height are equal?
CLASS - XI PHYSICS (Kinematics)
Answers
Answered by
4
Let the required angle be β.
Range =
maximum height =
So =
⇒
⇒tan β = 4
⇒ β = arctan(4)
⇒ β = 75.96⁰
Range =
maximum height =
So =
⇒
⇒tan β = 4
⇒ β = arctan(4)
⇒ β = 75.96⁰
Answered by
2
In kinematics we have the following formulas for the projectile motion:
It is useful to remember them or to derive them quickly.
time to reach the highest point = (u sin Ф /g)
R = 2 (u Sin Ф /g )(u cos Ф) = u² Sin 2Ф / g
H = (u sin Ф / g) (u Sin Ф/2) = u² Sin² Ф / 2g
H / R = tan Ф / 4
If H = R then tan Ф = 4 => Ф = 75.96°
It is useful to remember them or to derive them quickly.
time to reach the highest point = (u sin Ф /g)
R = 2 (u Sin Ф /g )(u cos Ф) = u² Sin 2Ф / g
H = (u sin Ф / g) (u Sin Ф/2) = u² Sin² Ф / 2g
H / R = tan Ф / 4
If H = R then tan Ф = 4 => Ф = 75.96°
Similar questions
Math,
8 months ago
Math,
8 months ago
Political Science,
8 months ago
Biology,
1 year ago
Math,
1 year ago