What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3π cm?
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SOLUTION:
Given:
Radius of Circle (r)= 6 cm
Length of an Arc (l)= 3π cm
If the radius of a circle is r ,θ be the angle and length of the arc is l, then
Length of the arc (l) = (θ /180) × πr
3 π= (θ /180) × π × 6
3 × 180 = θ × 6
θ =(3 × 180) / (6)
θ = 180 /2 = 90°
Hence, the angle subtended at the centre of a circle is 90°.
HOPE THIS WILL HELP YOU...
Given:
Radius of Circle (r)= 6 cm
Length of an Arc (l)= 3π cm
If the radius of a circle is r ,θ be the angle and length of the arc is l, then
Length of the arc (l) = (θ /180) × πr
3 π= (θ /180) × π × 6
3 × 180 = θ × 6
θ =(3 × 180) / (6)
θ = 180 /2 = 90°
Hence, the angle subtended at the centre of a circle is 90°.
HOPE THIS WILL HELP YOU...
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