what is the answer??????
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the answer is 18
because 3 balls can be put in 6 ways while keeping boxC as empty
and 3 balls can be put in 6ways while keeping boxB as empty
and 3 balls can be put in 6ways while keeping boxA as empty
so 6+6+6=18 ways
because 3 balls can be put in 6 ways while keeping boxC as empty
and 3 balls can be put in 6ways while keeping boxB as empty
and 3 balls can be put in 6ways while keeping boxA as empty
so 6+6+6=18 ways
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