Question

what is the answer ??​

Answer 1

$\binom{lim}{x →0 } \frac{x \cos(x) + \sin(x) }{ {x}^{2} + \tan(x) }$

$= > \binom{lim}{x →0 }\frac{x( \cos(x) + \frac{ \sin(x) }{x}) }{x(x + \frac{ \tan(x) }{x}) }$

$= > \frac{ \binom{lim}{x →0 } \cos(x) + \: \binom{lim}{x →0 } \frac{ \sin(x) }{x} }{ \binom{lim}{x →0 }x + \binom{lim}{x →0 } \frac{ \tan( x ) }{x} }$

$= > \frac{1 + 1}{0 + 1}$

$= > \frac{2}{1}$

$= > 2$

Answer 2

binom{lim}{x →0 }

$\binom{lim}{x →0 } \frac{x \cos(x) + \sin(x) }{ {x}^{2} + \tan(x) }$

$= > \binom{lim}{x →0 }\frac{x( \cos(x) + \frac{ \sin(x) }{x}) }{x(x + \frac{ \tan(x) }{x}) }$

$= > \frac{ \binom{lim}{x →0 } \cos(x) + \: \binom{lim}{x →0 } \frac{ \sin(x) }{x} }{ \binom{lim}{x →0 }x + \binom{lim}{x →0 } \frac{ \tan( x ) }{x} }$

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