What is the answer......
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by using the concept of wet
we have change of kinetic energy equal to the work done
so 1/2*m*v²=w
now
1/2*1500*16.67*16.67
this is required work done
we have change of kinetic energy equal to the work done
so 1/2*m*v²=w
now
1/2*1500*16.67*16.67
this is required work done
aryanverma123456781:
but answer is 208333.3 J
yes because when you will convert the speed in m/s you you can rake roundoff acc. to you answer i have taken it as 16.67
by the mine answer is approx right
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i have taken initial velocity as 0 m per sec.....starting initiaaly from rest.....
hope it helps.....
it's by work energy theorem..
hope it helps.....
it's by work energy theorem..
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but answer is 208333.3 J
:( ........ then don't know buddy.....
okk
make the kmper sec ...to m per sec
i forgot doing that
sorry...do the thing u will get the answer
thats what i was going to notify you
it will come 16.66
sorry foe that...i literally forgot
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