Math, asked by ashwin603109, 11 months ago

What is the answer and explain . I will mark brainliest

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Answered by harshit355
1
1/a+b+c = 1/a + 1/ b + 1/x
1/a+b+c =( bx+ab+ax) /(abx)
abx = abx+ b*2 x + bx*2 + a*2x + abx + ax*2 + a*2 b + ab *2+ abx
abx = 3abx + a*2 x + b*2 x + a*2 b + ab *2

-2abx = (a*2+b *2) x+ a*2 b + ab *2
-(a*2 +b*2 + 2 ab) x = a*2b + ab*2
x = -(a*2 b + a b*2)/(a+b)*2

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Answered by leslieware78
1

1/a+b+c = 1/a + 1/ b + 1/x

1/a+b+c =( bx+ab+ax) /(abx)

abx = abx+ b*2 x + bx*2 + a*2x + abx + ax*2 + a*2 b + ab *2+ abx

abx = 3abx + a*2 x + b*2 x + a*2 b + ab *2


-2abx = (a*2+b *2) x+ a*2 b + ab *2

-(a*2 +b*2 + 2 ab) x = a*2b + ab*2

x = -(a*2 b + a b*2)/(a+b)*2



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