Question

what is the answer for this​

Answer 1

$\sqrt{112} = 4 \sqrt{7}$

$d = \sqrt{7}$

$a4 = a + 3d = \sqrt{7} + 3 \sqrt{7} \\ a4 = 4 \sqrt{7}$

Answer 2

Answer:

a = $\sqrt{7}$

$\sqrt{28\\}$ = 2$\sqrt{7}$

$\sqrt{63}$ = 3$\sqrt{7}$

Therefore, d = $\sqrt{7}$

4th term = a + (n-1) d

              = a + 3d

              =$\sqrt{7}$ + 3$\sqrt{7}$

              = 4$\sqrt{7}$

Hope it helps!