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Hello Mate!
Given : ar(∆POQ) = ar(∆ROS)
To prove : PQRS is trapezium
Proof : ar(∆POQ) = ar(∆ROS) [ Given ]
Adding ar(∆POS) both sides we get,
ar(∆POQ) + ar(∆POS) = ar(∆ROS) + ar(∆POS)
ar(∆QPS) = ar(∆PSR)
Hence ∆QPS and ∆PSR are such two triangles that lie on same base PS and have same area so they must lie between same parallels too.
Therefore, PS || QR and hence PQRS is a trapezium since its one pair of opposite sides are parallel.
Hence proved.
Have great future ahead!
Given : ar(∆POQ) = ar(∆ROS)
To prove : PQRS is trapezium
Proof : ar(∆POQ) = ar(∆ROS) [ Given ]
Adding ar(∆POS) both sides we get,
ar(∆POQ) + ar(∆POS) = ar(∆ROS) + ar(∆POS)
ar(∆QPS) = ar(∆PSR)
Hence ∆QPS and ∆PSR are such two triangles that lie on same base PS and have same area so they must lie between same parallels too.
Therefore, PS || QR and hence PQRS is a trapezium since its one pair of opposite sides are parallel.
Hence proved.
Have great future ahead!
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minnie1204:
Thank you Genius!!! This really helps
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