Question

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Answer 1

Answer:

$\huge\underline\bold\red{Answer}$

The inside perimeter of the track=400m

The total length of the two straight portions=

90m+90m=180m

Therefore the length of the remaining portion=

400-180=220m

Circumference of the two remaining semi-circular portions=2πr units

2πr=220m

πr=110m

22r/7 = 110m

r=35m

So, the radius of the circular portion of the outer running running track=35+14=49m

Area of the track = Area of the two rectangles of dimensions + The area of the circular rings.

⇒ Area of track=2×90×14+ 22/7(49²-35²)

⇒ Area of track=2520m²+3696m²

⇒ Area of track=6216m²

⇒ Length of the outer running track =2×90+2× 22/7 ×49

⇒ Length of the outer running track =180m+308m

⇒ Length of the outer running track =488m