Math, asked by kunnurajput, 1 year ago

what is the answer of this Q 2y²+3y+1​

Answers

Answered by nazila101
1

2y² + 3y + 1 = 0

2y² + 2y + 1y + 1 = 0

2y ( y + 1) + 1 ( y + 1) = 0

(2y+1) (y+ 1) = 0

either 2y + 1 = 0 or y+ 1 = 0

i. e, y = – 1/2 or y = –1

Answered by sarikasingh16
2

product=2

sum=3

the number we will take =2 and 1

2y^2+2y+y+1

now we will take common

2y(y+1) 1(y+1)

=(2y+1) (y +1)

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