Question

What is the answer of this qn?

Answer 1

Answer:

sin45 = $\frac{1}{\sqrt{2} }$

tan30 = $\frac{1}{\sqrt{3} }$

Put the value of above and solve:

$\frac{4-1/2}{cot \theta \frac{1}{\sqrt{3} }} = 3.5$

$\frac{3.5}{cot\theta \frac{1}{\sqrt{3} }} = 3.5$

$cot\theta = \frac{1}{\sqrt{3} }$$\theta = 60 degree$

Answer 2

Answer:

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