What is the answer of this question
:4u^2-v^2-3uv+2u-2v
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Answer:
2(2u^2+u)-v(v-2)-3uv
Step-by-step explanation:
given
4u^2-v^2-3uv+2u-2v
=4u^2+2u-v^2-2v-3uv
=2(2u^2+u)-v(v-2)-3uv
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