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let age of seema be x and babita be 4x
Age of seema =4 times of babita.
x=4x.....(i)
now After, 4 years
x+4=4x+4
age of seema=twice the age of babita
x+4=2(4x+4)
=>x+4=8x+8
now x=4x
4x+4=8x+8
4x=4
x=1
babitas age is 4×1=4
seemas age is 1 year
and babita age is 4 years.
Age of seema =4 times of babita.
x=4x.....(i)
now After, 4 years
x+4=4x+4
age of seema=twice the age of babita
x+4=2(4x+4)
=>x+4=8x+8
now x=4x
4x+4=8x+8
4x=4
x=1
babitas age is 4×1=4
seemas age is 1 year
and babita age is 4 years.
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