Math, asked by aaty07, 1 year ago

what is the answer of this question ​

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Answered by 8334812253shinam
0
let age of seema be x and babita be 4x

Age of seema =4 times of babita.

x=4x.....(i)

now After, 4 years

x+4=4x+4

age of seema=twice the age of babita

x+4=2(4x+4)

=>x+4=8x+8

now x=4x

4x+4=8x+8

4x=4

x=1

babitas age is 4×1=4

seemas age is 1 year

and babita age is 4 years.
Answered by brunoconti
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