Question

what is the answer plss help me​

Answer 1

Refer to the attachment!!!

Answer 2

Step-by-step explanation:

Radius of the outer shell = r1

Radius of the inner shell = r2

The inner surface of the outer shell has charge +Q.

The outer surface of the inner shell has induced charge −Q.

Potential difference between the two shells is given by,

V=4πεor2Q−4πεor1Q

Where,

εo= Permittivity of free space

V=4πεor2Q−4πεor1Q

V=4πεoQ[r21−r11]

V=4πεor1r2Q(r1−r2)

Capacitance of the given system is given by,

C=VQ

C=r1−r24πεor1r2

Hence, proved.