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Answer:
In ∆ABC and ∆ABD we have ,
AC = AD. ( Given)
AB = AB. .. ( Common)
since, AB bisects /_A , therefore,
/_CAB = /_DAB
hence , ∆ABC =^~(congruent) ∆ABD by SAS
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Answered by
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Answer:
given- AC= AD
AB bisect A
To proove -ABC congruent to ABD
proof- AC=AD. (given)
AB=AB. (common)
A=A. (angle bisect into two
equal parts)
Therefore - ABCis congruent to triangle ABD. ( SAS)
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