Question

what is the area for rectangular hall in meter square , if it requires 60 tiles of length 300 centimetre and breadth 200 cm ​

Answer 1

L = 300 cm = 3m

B = 200 cm = 2m

Area of each tile = 6

$m^{2}$

Total area of wall = 60 × 6 = 360

${m}^{2}$

Answer 2

$\underline{\underline{\bold{Answer}}}$


360${m}^{2}$


$\huge\bold{Explanation}$


$\underline{\underline{\bold{Given}}}$


Length of the tile = 300cm = 3m.


Breadth of the tile = 200cm = 2m.


To cover the whole area of hall, we need 60 tiles of given length and breadth...


$\underline{\underline{\bold{To\:Find}}}$


Area of rectangular hall.


$\bold{We\:know\:that}$


$\boxed{\boxed{\bold{Area = length\times breadth}}}$


$\bold{According\:to\:the\:question}$


By using the upper given formula...let solve the following...


$\implies\bold{Area\:of\:tile = l\times b}$


$\implies\bold{3m\times 2m}$


$\implies\bold{6{m}^{2}}$


As given in the question that the rectangular hall requires 60 tile to cover the area....so ,


Area of rectangular hall = 60 × 6${m}^{2}$


$\implies{360{m}^{2}}$


So the final answer is -


$\boxed{\boxed{\bold{\therefore{360{m}^{2}}}}}$