Question

What is the area of a rectangle with base, B = 22mm and perimeter, P = 64mm

Answer 1

Answer:

p=2(l+22)=64

l+22=32

l=10

Answer 2

${ \red{ \huge{ \bold{ \underline{ \underline{ \: question}}}}}}$

what is the area of a rectangle with base , B = 22mm and perimeter , P = 64mm


${ \red{ \huge{ \bold{ \underline{ \underline{ \: solution}}}}}}$

${ \purple{ \huge{ \: given}}}$

${ \bold{ \: base \: of \: rectangle \: = \: 22mm}}$

${ \bold{ \: perimeter \: = \: 64mm}}$

${ \purple{ \huge{ \: to \: find}}}$

${ \bold{ \: area \: of \: rectangle}}$

$\red{ \: for \: a \: rectangle}$

${ \boxed{ \bold{ \: perimeter \: = \: 2( \: l \: + \: b)}}}$


${ \boxed{ \bold{ \: area \: = \: l \times b}}}$

${ \bold{ \implies{ \: 64mm \: = \: 2( \: l \: + \: 22mm)}}}$

${ \bold{ \implies{ \:64mm \: = \: 2l \: + \: 44mm}}}$

${ \bold{ \implies{ \: 2l \: = \: 64mm \: - \: 44mm}}}$

${ \bold{ \implies{ \: 2l \: = \: 20mm}}}$

${ \bold{ \: length(l) \: = \: 10mm}}$


${ \pink{ \: area \: of \: rectangle}}$

${ \pink{ \: = \: length \: \times \: breadth}}$

${ \bold{ \: = \: 22mm \: \times \: 10mm}}$

${ \bold{ \: = \: 220 {mm}^{2} }}$


${ \red{ \huge{ \bold{ \underline{ \underline{ \: answer}}}}}}$

therefore,

area of rectangle = 220 mm square


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