Question

What is the area of a rhombus whose diagonals are (x+2)cm and (x-7)cm.

Answer 1

Given diagonals (x+2) and (x-7)
So
area of rhombus = (diagonal ×diagonal )/2
= {(x+2)(x-7)}/2
= (x^2-7x+2x-14)/2
= (x^2-5x-14)/2 cm^2 is right answer

Answer 2

Area Of Rhombus = ( Product of Diagonal ) / 2

Area of Rhombus = ( [ x+2)(x-7) ] / 2

= ( x²-7x+2x-14 ) 2

= (x²-5x-14) / 2

= [ x²-(7-2)x-14] / 2

= (x²-7x+2x-14) / 2

= [X ( x-7) +2 (x-7) ] / 2

= [ (x-7) (x+2) ] / 2 Ans

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