Question

*What is the area of a rhombus with side 10 cm and length of the diagonal 16 cm?*

1️⃣ 80 sqcm
2️⃣ 128 sqcm
3️⃣ 48 sqcm
4️⃣ 96 sqcm​

Answer 1

Given :   a rhombus with side 10 cm and length of the diagonal 16 cm

To Find   : area of a rhombus

1️⃣ 80 sqcm

2️⃣ 128 sqcm

3️⃣ 48 sqcm

4️⃣ 96 sqcm​

Solution:

Diagonals of rhombus bisect each other at right angles

Diagonal 1  = 16 cm

Half of diagonal = 16/2  = 8 cm

√10² - 8²  = 6 cm  ( half of other diagonal)

=> other diagonal = 12 cm

area of a rhombus  = (1/2) * product of diagonals

= (1/2) * 16 * 12

= 96 cm²

Learn More:

If the area of a trapezium with parallel sides of length 30 cm and 23 ...

brainly.in/question/4717262

Find the area of trapezium in which parallel sides are of length 5 cm ...

brainly.in/question/3877026

Answer 2

• Diagonal 1 (D) = 16 cm
• Half of Diagonal (H) = 16/2 = 8 cm
• Side (S) = 10 cm
• Diagonal 2 (d) = ???
• then ,
• (d)² = (S)² - (H)² = (10)² - (8)² = 100 - 64 = 36
• d = √36 = 6 cm
• then ,
• Diagonal 2 = 2H = 2(6) = 12 cm
• then ,
• Area of Rhombus = ½ × ( Product of its diagonals ) = ½ × 12 × 16 = 6 × 16 = 96 cm²
• Area of Rhombus = 96 cm²
• Thus , option 4⃣ → 96 cm² is correct

Mark as Brainliest answer please my friend

Hope this will help u