Question

*What is the area of a rhombus with side 10 cm and length of the diagonal 16 cm?*

1️⃣ 80 sqcm
2️⃣ 128 sqcm
3️⃣ 48 sqcm
4️⃣ 96 sqcm​

Answer 1

Answer:

area = 4) 96sqcm

Step-by-step explanation:

by this by applying Pythagoras theoram we get the other diagonal = 2×6 =12cm

now area of rhombus= d1 ×d1÷2

here d1= 16cm

d2= 12cm

so area =1/2 ×16×12

= 96cm²

thank you

Answer 2

Given :- What is the area of a rhombus with side 10 cm and length of the diagonal 16 cm?*

1) 80 sqcm

2) 128 sqcm

3) 48 sqcm

4) 96 sqcm

Answer :-

Let other diagonal length is 2d cm.

since diagonals of a rhombus bisect each other at 90° .

using pythagoras theorem,

→ (16/2)² + (2d/2)² = 10²

→ 8² + d² = 100

→ d² = 100 - 64

→ d = √36

→ d = 6cm.

then,

→ length of another diagonal = 2d = 2 * 6 = 12 cm.

therefore,

→ Area of parallelogram = (1/2) * D1 * D2 = (1/2) * 16 * 12 = 96 cm² (4) (Ans.)

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