Question

*What is the area of a rhombus with side 10 cm and length of the diagonal 16 cm?*

1️⃣ 80 sqcm
2️⃣ 128 sqcm
3️⃣ 48 sqcm
4️⃣ 96 sqcm​

Answer 1

Answer:

Answer is 4) 9 sqcm

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Answer 2

Answer:

4. 96 sq.cm

Step-by-step Explanation

Diagonals of a rhombus bisect each other at right angles.

Let ABCD be the rhombus, Diagonal

AC = 16 cm and side AB = 10 cm.

In right △AOB, AB = 10 cm, AO = 8 cm

By Pythagoras theorem, AB² = AO² + BO²

⇒ 10² = 8² + BO²

⇒ BO² = 100 - 64 = 36

∴ BO = 6cms

Diagonal BD = 2 × 6 = 12cm

Area of Rhombus = 1/2×(productofthediagonals)

= 1/2 × 16 × 12

= 8 × 12

= 96 sq.cm

∴ Area of rhombus = 96sq.cm

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