Question

What is the area of a trapezium whose parallel sides are 25 cm and 15 cm and 12 cm height?
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Answer 1

240 cm^2

Step-by-step explanation:

area of trapezium = 1/2 × sum of parallel sides × height or a+b/2 ×h

25 + 15/2 × 12 = 40/2 × 12 = 20 × 12 = 240 cm^2

Answer 2

Given :

⬤ Parallel Sides of Trapezium are 25 cm and 15 cm .

⬤ Height of Trapezium = 12 cm

To Find :

⬤ Area of Trapezium .

Formula Used :

$\small\sf[\:{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Sides)}\times{h}\:]}$

Solution :

• Parallel Sides = 25 cm , 15 cm
• Height = 12 cm
• Area = ?

According to the Formula :

1/2 × (25 + 15) × 12

37 × 6

222

Therefore , The Area of Trapezium is 222 cm² .

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Related Formulas :

• Area of Trapezium = ½ × (Sum of Parallel Sides) × h
• Area of Rectangle = l × b
• Area of Square = Side × Side
• Area of Parallelogram = b × h
• Area of Triangle = 1/2 × b × h
• Area of Circle = πr²

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