Question

What is the area of a triangle whose base is 18.2cm and height 9 cm?

Answer 1

Answer:

★ Area = 81.9 or 82 Cm² ★

Step-by-step explanation:

Given:

• Length of base of triangle is 18.2 cm
• Height of triangle is 9 cm

To Find:

• Area of the triangle

Solution: Formula for finding area of triangle

★ Area of Triangle = 1/2 x ( Base x Height ) ★

• Putting the values in formula •

$\small\implies{\sf }$ 1/2 x ( 18.2 x 9 )

$\small\implies{\sf }$ 1/2 x 163.8

$\small\implies{\sf }$ 81.9 Cm²

Hence, Area of Triangle is 81.9 cm² or 82 cm²

Answer 2

Answer:

To Find:-

Area of the triangle whose

• Base: 18.2 cms
• Height: 9 cms

REQUIRED SOLUTION:-

We know that,

Area of the triangle:

$\frac{1}{2} \times (base) \times (height)$

Therefore, according to the formula,

$\frac{1}{2} \times (18.2) \times (9) \ c.m. \times c.m.$

(Putting the values of height and base which are given)

$= \frac{1}{\cancel{2}} \times \frac{\cancel{182}}{10} \times 9 \ c.m. \times c.m.$

{Converted 18.2 to its fractional form eliminating (.) and taking (10) as denominator. Cancellation of 2 and 182,

• 2(91) = 182
• 2(1) = 2}

$= 1 \times 9.1 \times 9 \ c.m. \times c.m.$

(After Operation between the numbers \ Result \ Also written in its decimal form)

$= 81.9 \ {cm}^{2}$

(Solution)

THEREFORE,

Area of the triangle is 81.9 cm².