What is the area of right triangle with base of length 12 cm and hypotenuse of length 20 cm
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Answer:
Step-by-step explanation:
using pythagoras theorem,
h^2=p^2+b^2
20^2=p^2+12^2
400-144=p^2
p^2=256
p=16
ht=16cm
area=1/2*b*ht
area=1/2*12*16=96cm^2
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