Question

What is the area of segment ACB, If the arc AB subtends an angle of 45° at the centre and the radius of the circle is 10.5 cm? The length of the chord is 7 cm. Take
$\sqrt{98} = 9.9$

Please answer it
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Answer 1

Answer:

The Area of segment ACB is 43.27 square centimeter .

Step-by-step explanation:

Given as :

The angle subtended at the centre of circle = Ф = 45°

The radius of the circle = r = 10.5 cm

Let The Area of the segment ACB = A

According to question

Area of segment = π × radius² × $\frac{\Theta }{360}$

Or, A = 3.14 × 10.5² × $\frac{45^{\circ} }{360^{\circ}}$

Or, A = 3.14 × 110.25 × $\frac{45^{\circ} }{360^{\circ}}$

Or, A = 346.185 × 0.125

∴ A = 43.27 cm²

So, The Area of the segment ACB = A = 43.27 cm²

Hence, The Area of segment ACB is 43.27 square centimeter . Answer