Math, asked by reenakadyan0011, 2 months ago

What is the area of the biggest triangle inscribed in a semicircle with a radius of 5 cm?​

Answers

Answered by aditikanwadkar
2

Step-by-step explanation:

We first need to know;  

that area is multiplication of 1/2, base, and height.

If area is maximum, then base and height are also maximum.  

The specific case of that will happen;  

when base is a diameter of circle and when height is a radius.

Now,  

1/2 × Base × Height  

= 1/2 × Diameter × Radius

= 1/2 × 10 × 5  

= 25

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Answered by chaubeysanjay1975
0

Step-by-step explanation:

The area of a triangle is equal to the base times the height.

In a semi circle, the diameter is the base of the semi-circle.

This is equal to 2×r (r = the radius)

If the triangle is an isosceles triangle with an angle of 45

The area of a triangle is equal to the base times the height.

In a semi circle, the diameter is the base of the semi-circle.

This is equal to 2×r (r = the radius)

If the triangle is an isosceles triangle with an angle of 45 The area of a triangle is equal to the base times the height.

In a semi circle, the diameter is the base of the semi-circle.

This is equal to 2×r (r = the radius)

If the triangle is an isosceles triangle with an angle of 45∘at each end, then the height of the triangle is also a radius of the circle.

A = 5/2×b×h formula for the area of a triangle becomes

A = 5/2×2×r×r because:

The base of the triangle is equal to 5×r

The height of the triangle is equal to 5

A = 5/2×2×r×r

A=5r square

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