What is the area of the biggest triangle inscribed in a semicircle with a radius of 5 cm?
Answers
Step-by-step explanation:
We first need to know;
that area is multiplication of 1/2, base, and height.
If area is maximum, then base and height are also maximum.
The specific case of that will happen;
when base is a diameter of circle and when height is a radius.
Now,
1/2 × Base × Height
= 1/2 × Diameter × Radius
= 1/2 × 10 × 5
= 25
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Step-by-step explanation:
The area of a triangle is equal to the base times the height.
In a semi circle, the diameter is the base of the semi-circle.
This is equal to 2×r (r = the radius)
If the triangle is an isosceles triangle with an angle of 45
The area of a triangle is equal to the base times the height.
In a semi circle, the diameter is the base of the semi-circle.
This is equal to 2×r (r = the radius)
If the triangle is an isosceles triangle with an angle of 45 The area of a triangle is equal to the base times the height.
In a semi circle, the diameter is the base of the semi-circle.
This is equal to 2×r (r = the radius)
If the triangle is an isosceles triangle with an angle of 45∘at each end, then the height of the triangle is also a radius of the circle.
A = 5/2×b×h formula for the area of a triangle becomes
A = 5/2×2×r×r because:
The base of the triangle is equal to 5×r
The height of the triangle is equal to 5
A = 5/2×2×r×r
A=5r square