Question

what is the area of the circle whose radius is the diagonal of a square whose area is 4

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

8π

Step-by-step explanation:

Area of square = 4

Let side of square be x.

So, x*x = 4

∴ x = 2.

If we take any 2 adjacent sides and the corresponding diagonal, an isosceles right angled triangle is formed.

So, 2² + 2² = (diagonal)²

Diagonal = √8

Radius of circle = Diagonal = √8

Area of circle = π*r²

                       = 8π

                       = 25.13

Hope this helps! :)