Question

what is the area of the plates of a 2microfarad parallel plate capacitor , given that the separation b/w the plates is 0.05 cm?​

Answer 1

Given, Capacitance for parallel plate capacitor, C= 2μF

And gap between the plates, d= 0.05 cm

We know, Capacitance for parallel plate capacitor  C= ε₀A/d

Where A is the area of the plates.

Now,

A= C.d/ ε₀

   [Here ε₀= 8.85×10⁻¹²Fm⁻¹]

So, A= (2×10⁻⁶×0.05×10⁻²)/ 8.85×10⁻¹²

        = 113 m²