Question

what is the area of the shaded portion,equilateral triangle side is 6cm and radius is 1.5cm​

Answer 1

Answer:

Step-by-step explanation:

Given AB=BC=CA=6cm

⇒  We have O as the circumcenter

⇒  ∠OBA=30o

In △BOM,

⇒   cos30o=BOBM

⇒  23=r3

∴  r=23cm

⇒  Area of shaded region = Area of circle - Area of △ABC

⇒  Area of shaded region =πr2−43×(side)2

⇒  Area of shaded region =(3.14)×(23)2−43×(6)2

⇒  Area of shaded region =37.68−15.59

∴  Area of shaded region =22.126cm2



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Answer 2

Answer:

Step-by-step explanation:

Given AB=BC=CA=6cm

⇒  We have O as the circumcenter

⇒  ∠OBA=30o

In △BOM,

⇒   cos30o=BOBM

⇒  23=r3

∴  r=23cm

⇒  Area of shaded region = Area of circle - Area of △ABC

⇒  Area of shaded region =πr2−43×(side)2

⇒  Area of shaded region =(3.14)×(23)2−43×(6)2

⇒  Area of shaded region =37.68−15.59

∴  Area of shaded region =22.126cm2

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