Question

what is the area of the triangle ACB in square unit if a is the centre of the circle ? if B = (6,4) and D = (8,0) please answer it ​

Answer 1

Answer:

Given: Coordinates of Point A(1,3),B(−1,0) and C(4,0)

Construction: Drop a perpendicular from A on x− axis, which meets x-axis at D≡(1,0)

Now in ΔADC,AD=3,DC=3

Area of ΔADC=

2

1

×DC×AD

=

2

1

×3×3=

2

9

cm

2

Now in ΔADB,AD=3,DB=2

Area of ΔADB=

2

1

×DB×AD

=

2

1

×2×3=3 cm

2

Area of ΔABC= Ara of ΔADC+ Area of ΔABD

=

2

9

+3=

2

15

=7.5 cm

2

I hope it's help you

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