What is the area of this triangle?
Attachments:
Answers
Answered by
1
Hi Mate!!!
Area of a trangle having co-ordinates ( x1, y1 ) ( x2, y2) and. (x3,y3)
= 1/2[ x1 ( y2 - y3 ) + x2(y3-y1) +x3 ( y1-y2)
But here. x2 = x1
Itz area = 1/2[x1( y2 -y3 + y3 -y1 )+x3(y1-y2)]
= 1/2 ( y2 -y1 ) [ x1 - x3]
Area of a trangle having co-ordinates ( x1, y1 ) ( x2, y2) and. (x3,y3)
= 1/2[ x1 ( y2 - y3 ) + x2(y3-y1) +x3 ( y1-y2)
But here. x2 = x1
Itz area = 1/2[x1( y2 -y3 + y3 -y1 )+x3(y1-y2)]
= 1/2 ( y2 -y1 ) [ x1 - x3]
Similar questions