Question

what is the area of tiangle whose base is 4.9 and height is 10.2

Answer 1

area of triangle=1/2×base×height
=1/2×4.9×10.2
=4.9×5.1
=24.99 square units

Answer 2

base=4.9
height=10.2
area of Δ=½×base×height

$\frac{1}{2} \times base \times height$

$\frac{1}{2} \times \frac{49}{10} \times \frac{102}{10}$

$\frac{4998}{200} = \frac{2494}{100} = \frac{1247}{50} = 24.94$cm²

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