what is the area of trapezium
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Let ABCD be a trapezium in which AB ∥ DC, CE ⊥ AB, DF ⊥ AB and CE = DF = h. Prove that: Area of a trapezium ABCD = {¹/₂ × (AB + DC) × h} square units.
piyush443:
ya
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Hey buddy!
Here's your answer ▪_⬇️_▪
The Area Of Trapezium
= 1/2×(Sum of lengths of parallel sides)×height.
Hope it helps you!
☺ ☺ ☺
Here's your answer ▪_⬇️_▪
The Area Of Trapezium
= 1/2×(Sum of lengths of parallel sides)×height.
Hope it helps you!
☺ ☺ ☺
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