What is the area of triangle ACD if AD=15cm,DC=28cm,AC=41cm
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Answered by
2
Answer:
Area=S(S-A) (S-B) (S-C) where S is semiperimetre and ABC are sides
Answered by
3
Answer:
s=(41+28+15)/2= 84/2=42
by Heron's formula
Area = √s(s-a)(s-b)(s-c)
where a,b,c are the sides of triangle .
=> √ 42×1×14×27
=> 126 sqcm
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