Question

what is the area of triangle whose sides are 16cm 30cm 34cm (using heron's formula

Answer 1

S = (a+b+c) /2
= (16+30+34)/2
= 80/2
=40
Area of triangle =under root 40(40-16)(40-30)(40-34)
=under root 40*26*10*6
=under root 62400
=249.79

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=240\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle = 16 cm,30 cm,34 cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{16+ 30+ 34}{2} \\ \\ : \implies s = \frac{80}{2} \\ \\ \green{ : \implies s = 40} \\ \\ \circ\: \bold{Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{40(40- 16)(40-30)(40-34)} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{40 \times 24\times 10\times 6} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{57600} \\ \\ : \implies \text{Area \: of \: triangle =}240 \: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle = 240 {cm}}^{2} }$