Question

what is the average kinetic energy per molecule of an ideal gas at 27 °C (where NA is
Avogadro's number)?​

Answer 1

Answer:

Mean KE=

2

3kT

so 6.21×10

−21

=3k×300/2

so k=1.38×10

−23

KE at 500 K ,KE=3×1.38×10

−23

×500/2=10.35×10

−21

Joule

Explanation:

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