What is the braking force at the end of 5 seconds to bring the car to a stop within one second?
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Answered by
11
Since F=ma,
and a= ∆v/∆t
we have a= -15 m/s²
Therefore F=(1000)(-15) N
= -15000N (Mass, given : 1000kg)
and a= ∆v/∆t
we have a= -15 m/s²
Therefore F=(1000)(-15) N
= -15000N (Mass, given : 1000kg)
wboy:
yhanks bro
We've taken the time during which the car decelrated, ie between the 5th and 6th second.
Also, since the accelareation should come out negative (sorry, didn't mention), -15m/s², the force is -15000N
it's okkk
your actual answer is right
Okay. They might not have considered the force's direction. Either way, it's correct.
Answered by
13
Answer:
Acceleration = Change in velocity /time
Time = 1 sec
Initial velocity = 15m/s1
Final velocity =0
=> Acceleration = 15-0/1
= 15 m/s^2
Force = Mass × Acceleration
Force = 1000 kg × 15 m/s ^2
Force = 15000 N
Explanation:
We used 1sec as time because in the question it is mentioned to stop the car .therefore it is needed to take time as 1. Final velocity is 0 because the car will be at rest.
I hope it helps...
Please mark me brainliest..
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