Math, asked by karlahiyas, 3 months ago

What is the center of a circle if the equation is (x²)+(y-4)²=5²

Answers

Answered by gopalpvr

0

Answer:

centre = (0, 4)

Step-by-step explanation:

(x²)+(y-4)²=5²

=> (x-0) ²+(y-4)²=5²

=> centre = (0, 4)

we know that

(x-a) ²+(y-b)²=r² ( a, b) us centre, r is radius

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