what is the centre of mass of a cube of side a if 4 corners of it have m masses and other 4 corners have 2m masses
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Let us consider O as origin.
So, x
cm
=
m
1
+m
2
+m
3
+m
4
m
1
X
1
+m
2
X
2
+m
3
X
3
+M
4
X
4
=
10
3×0+2×2+1×2+2×0
=
10
6
=
5
3
Similarly, y
cm
=
10
3×0+2×0+1×2+4×2
=
10
10
=1
∴ COM at (
5
3
,1)
or
5
2
m left of center of square.
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