What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km/h to 72 km/h uniformly?plz do not skip any step show all the step clearly.
Answers
Answered by
10
Given mass m = 1500 kg
u = 36 km/h
= 36*5/18
= 10 m/s
v = 72 km/h
= 72*5/18
= 20 m/s
We know that change in momentum = mv - mu
= 1500 * 20 - 1500 * 10
= 1500(20-10)
= 1500 * 10
= 15000 kg m/s.
Hope this helps!
u = 36 km/h
= 36*5/18
= 10 m/s
v = 72 km/h
= 72*5/18
= 20 m/s
We know that change in momentum = mv - mu
= 1500 * 20 - 1500 * 10
= 1500(20-10)
= 1500 * 10
= 15000 kg m/s.
Hope this helps!
Answered by
2
∆p=m×(final velocity -initial velocity)=
1500×(20 -10). [becuz 18km/h= 5m/s]
= 15000kgm/s.
1500×(20 -10). [becuz 18km/h= 5m/s]
= 15000kgm/s.
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