what is the change in the kinetic energy of a body if its velocity is doubled and the mass is halved?
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as it be ke =1/2mv²so acc to condition so substitute m by m/2 and v by 2v so we get
=1\2*m/2*(2v)²= m/4*4v²=mv² so we get twice of original kE and new ke=2kE
=1\2*m/2*(2v)²= m/4*4v²=mv² so we get twice of original kE and new ke=2kE
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