Question

What is the coefficient of viscosity of the oil which flows at the rate of
420 cc/min through a tube of length 100 cm and internal diameter 2 mm
under a pressure difference of 30 N/m² ?​

Answer 1

The coefficient of viscosity is 2.8 centipoise.

Explanation:

Q = △Pπr^2 / 8ηl

Given data:

Length L = 100 cm = 1 m

△P = 30 N /m^2

d = 2 mm = 2 x 10^-3 m

Radius r = 1 x 10^-3 m

Rate of flow Q = 420 cm^3 / min

Solution:

η = △Pπr^2 / 8Ql

η =  30 x 3.14 x (1 x 10^-3)^2 / 8 x 420 x 1

η =  94.2 x 10^-6 / 3360

η =   2.8 centipoise

Thus the coefficient of viscosity is 2.8 centipoise.

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