Question

what is the coefficient of x^2 then the question is (2-3x^2)(x^2-5)

Answer 1

$= > (2 - {3x}^{2} )( {x}^{2} - 5)$

$= > 2( {x}^{2} - 5) - {3x}^{2} ( {x}^{2} - 5)$

$= > 2 {x}^{2} - 10 - 3 {x}^{4} + 15 {x}^{2}$

$= > - 3 {x}^{4} + 17 {x}^{2} - 10$

• Cᴏᴇғғɪᴄɪᴇɴᴛ ᴏғ x^(2) = 17

• Cᴏᴇғғɪᴄɪᴇɴᴛ ᴏғ x^(4) = -3

ᕼOᑭᗴ IT ᕼᗴᒪᑭՏ..!

Answer 2

$\sf{Answer}$

Step by step explanation:-

Given :-

(2-3x²)(x²-5)

To find :-

Coefficient of x²

Solution :-

(2 - 3x² ) ( x² -5)

2(x² - 5) -3x² ( x² -5)

2x² -10 - 3x⁴+ 15x²

2x² - 3x⁴ - 10 + 15x²

-3x⁴ + 2x² + 15x² -10

-3x⁴ + 17x² -10

Now,

-3 is coefficient of x⁴

17 is coefficient of x²

-10 is constant term

Coefficient of x² is 17

Hope u helpful..