Question

what is the common difference of an ap if its nth term is 7n -1

Answer 1

N th term =7n-1
So first term = 7(1)-1=6
Second term= 7(2)-1=13
Common difference= second - first
=13-6
=7

Answer 2

Answer:

$Common\:difference (d)=7$

Step-by-step explanation:

$Given\: n^{th}\: term \: of \:A.P = \\t_{n}=7n-1$

$We \: know \: that ,\\\boxed {Common \: difference (d)= t_{n}-t_{n-1}}$

Now ,

$d = 7n-1-[7(n-1)-1]$

$\implies d = 7n-1-(7n-7-1)$

$\implies d = 7n-1-7n+7+1$

$\implies d =7$

Therefore,

$Common\:difference (d)=7$

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