what is the common difference of an ap which a 12 minus 8 is equal to 24
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Answered by
6
a12-a8=24
a+11d-a+7d=24
18d=24
d=4/3
a+11d-a+7d=24
18d=24
d=4/3
Answered by
11
Answer: 6
explanation -->
given 12th term of AP - 8th term of AP = 24 -- (1)
nth term of AP = a +(n-1)d [where a = first term, d = common difference]
----
12th term = a + 11d
8th term = a + 7d
from (1), substituting
(a+11d) - (a+7d) = 24
4d = 24
d = 6
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